64 lines
2.7 KiB
Markdown
64 lines
2.7 KiB
Markdown
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# Space Age
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Welcome to Space Age on Exercism's jq Track.
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If you need help running the tests or submitting your code, check out `HELP.md`.
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## Introduction
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The year is 2525 and you've just embarked on a journey to visit all planets in the Solar System (Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune).
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The first stop is Mercury, where customs require you to fill out a form (bureaucracy is apparently _not_ Earth-specific).
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As you hand over the form to the customs officer, they scrutinize it and frown.
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"Do you _really_ expect me to believe you're just 50 years old?
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You must be closer to 200 years old!"
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Amused, you wait for the customs officer to start laughing, but they appear to be dead serious.
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You realize that you've entered your age in _Earth years_, but the officer expected it in _Mercury years_!
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As Mercury's orbital period around the sun is significantly shorter than Earth, you're actually a lot older in Mercury years.
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After some quick calculations, you're able to provide your age in Mercury Years.
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The customs officer smiles, satisfied, and waves you through.
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You make a mental note to pre-calculate your planet-specific age _before_ future customs checks, to avoid such mix-ups.
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~~~~exercism/note
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If you're wondering why Pluto didn't make the cut, go watch [this YouTube video][pluto-video].
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[pluto-video]: https://www.youtube.com/watch?v=Z_2gbGXzFbs
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~~~~
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## Instructions
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Given an age in seconds, calculate how old someone would be on a planet in our Solar System.
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One Earth year equals 365.25 Earth days, or 31,557,600 seconds.
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If you were told someone was 1,000,000,000 seconds old, their age would be 31.69 Earth-years.
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For the other planets, you have to account for their orbital period in Earth Years:
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| Planet | Orbital period in Earth Years |
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| ------- | ----------------------------- |
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| Mercury | 0.2408467 |
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| Venus | 0.61519726 |
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| Earth | 1.0 |
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| Mars | 1.8808158 |
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| Jupiter | 11.862615 |
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| Saturn | 29.447498 |
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| Uranus | 84.016846 |
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| Neptune | 164.79132 |
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~~~~exercism/note
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The actual length of one complete orbit of the Earth around the sun is closer to 365.256 days (1 sidereal year).
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The Gregorian calendar has, on average, 365.2425 days.
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While not entirely accurate, 365.25 is the value used in this exercise.
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See [Year on Wikipedia][year] for more ways to measure a year.
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[year]: https://en.wikipedia.org/wiki/Year#Summary
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~~~~
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## Source
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### Created by
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- @glennj
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### Based on
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Partially inspired by Chapter 1 in Chris Pine's online Learn to Program tutorial. - https://pine.fm/LearnToProgram/?Chapter=01
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