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exercism/jq/collatz-conjecture
Christina Sørensen 8bee36be78
feat(jq): scrabble, hamming, etl, collatz
Signed-off-by: Christina Sørensen <christina@cafkafk.com>
2024-12-16 16:22:26 +01:00
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.exercism feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
bats-extra.bash feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
bats-jq.bash feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
collatz-conjecture.jq feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
HELP.md feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
README.md feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00
test-collatz-conjecture.bats feat(jq): scrabble, hamming, etl, collatz 2024-12-16 16:22:26 +01:00

Collatz Conjecture

Welcome to Collatz Conjecture on Exercism's jq Track. If you need help running the tests or submitting your code, check out HELP.md.

Instructions

The Collatz Conjecture or 3x+1 problem can be summarized as follows:

Take any positive integer n. If n is even, divide n by 2 to get n / 2. If n is odd, multiply n by 3 and add 1 to get 3n + 1. Repeat the process indefinitely. The conjecture states that no matter which number you start with, you will always reach 1 eventually.

Given a number n, return the number of steps required to reach 1.

Examples

Starting with n = 12, the steps would be as follows:

  1. 12
  2. 6
  3. 3
  4. 10
  5. 5
  6. 16
  7. 8
  8. 4
  9. 2
  10. 1

Resulting in 9 steps. So for input n = 12, the return value would be 9.

Source

Created by

  • @glennj

Based on

An unsolved problem in mathematics named after mathematician Lothar Collatz - https://en.wikipedia.org/wiki/3x_%2B_1_problem