main: require argv[0]
sure, linux has been providing argv[0] by default for a while now. other OSes may not be as forthcoming though, and relying on the OS to create a world in which we can just make assumptions we could test for instead is unnecessarily lazy. we *could* default argv0, but that's a little silly. notably we abort instead of returning normally to avoid confusions where a caller interprets our exit status like a Worker build results bitmask. Change-Id: Id73f8cd0a630293b789c59a8c4b0c4a2b936b505
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@ -503,6 +503,11 @@ void mainWrapped(int argc, char * * argv)
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int main(int argc, char * * argv)
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int main(int argc, char * * argv)
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{
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{
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if (argc < 1) {
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std::cerr << "no, we don't have pkexec at home. provide argv[0]." << std::endl;
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std::abort();
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}
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// Increase the default stack size for the evaluator and for
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// Increase the default stack size for the evaluator and for
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// libstdc++'s std::regex.
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// libstdc++'s std::regex.
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nix::setStackSize(64 * 1024 * 1024);
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nix::setStackSize(64 * 1024 * 1024);
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